A plane flying at 70.0 m/s suddenly stalls. If the acceleration during the stall is 9.8 m/s2 directly downward, the stall lasts 5.0 s, and the plane was originally climbing at 25° to the horizontal, what is the velocity after the stall?

Respuesta :

Answer:

v = 66.4 m/s

Explanation:

As we know that plane is moving initially at speed of

[tex]v = 70 m/s[/tex]

now we have

[tex]v_x = 70 cos25[/tex]

[tex]v_x = 63.44 m/s[/tex]

[tex]v_y = 70 sin25[/tex]

[tex]v_y = 29.6 m/s[/tex]

now in Y direction we can use kinematics

[tex]v_y = v_i + at[/tex]

[tex]v_y = 29.6 - (9.81 \times 5)[/tex]

[tex]v_y = -19.5 m/s[/tex]

since there is no acceleration in x direction so here in x direction velocity remains the same

so we will have

[tex]v = \sqrt{v_x^2 + v_y^2}[/tex]

[tex]v = \sqrt{63.44^2 + 19.5^2}[/tex]

[tex]v = 66.4 m/s[/tex]