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When you float an ice cube in water, you notice that 90% of it is submerged beneath the surface. Now suppose you put the same ice cube in a glass of some liquid whose density is less than that of water.

How much of the ice cube will be submerged below the surface of this liquid?

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Answer:

more than 90%

Explanation:

In the unknown liquid the buoyant force and weight relation is

[tex]V\rho_lg=mg\\\Rightarrow V\rho_l=m[/tex]

It can be seen that if the density decreases the buoyant force decreases.

If the object is already 90% submerged in water then, if the other liquid has density less than that of water the object will be submerged more than 90%.

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