Answer: 3 neutrons are produced in the above nuclear reaction.
Explanation:
In a nuclear reaction, the total mass and total atomic number remains the same.
The nuclear reaction for the fission of Americium-244 isotope follows:
[tex]^{244}_{95}\textrm{Am}\rightarrow ^{134}_{53}\textrm{I}+^{107}_{42}\textrm{Mo}+Y^1_0\textrm{n}[/tex]
To calculate Y:
Total mass on reactant side = total mass on product side
[tex]\Rightarrow 244=134+107+(Y\times 1)\\\\\Rightarrow Y=244-241=3[/tex]
Hence, 3 neutrons are produced in the above nuclear reaction.
The nuclear equation for the spontaneous fission of ₉₅Am²⁴⁴ to form ₅₃I¹³⁴ + ₄₂Mo¹⁰⁷ produces three neutrons and is given below:
.
A nuclear equation is an equation showing the changes that occurs in the nucleus of an atom.
The nuclear equation for the spontaneous fission of ₉₅Am²⁴⁴ to form ₅₃I¹³⁴ + ₄₂Mo¹⁰⁷ is given below:
₉₅Am²⁴⁴ -----> ₅₃I¹³⁴ + ₄₂Mo¹⁰⁷ + 3 ₀n¹
From the above reaction, three neutrons are produced.
Learn more about nuclear fission at: https://brainly.com/question/1358872
