Answer:
[tex]y=5x-13[/tex]
Step-by-step explanation:
The correct question is
What is the equation of a line passing through the point (3, 2) and parallel to the line y=5x+4
step 1
Find the slope of the given line
we have
[tex]y=5x+4[/tex]
This is the equation of the line in slope intercept form
The slope is [tex]m=5[/tex]
step 2
Find the slope of the line parallel to the given line
we know that
If two lines are parallel, then their slopes are equal
so
The slope is [tex]m=5[/tex]
step 3
Find the equation of the line in point slope form
[tex]y-y1=m(x-x1)[/tex]
we have
[tex]m=5[/tex]
[tex]point\ (3,2)[/tex]
substitute
[tex]y-2=5(x-3)[/tex]
step 4
Convert to slope intercept form
[tex]y=mx+b[/tex]
isolate the variable y
[tex]y-2=5x-15[/tex]
[tex]y=5x-15+2[/tex]
[tex]y=5x-13[/tex]
