Answer:
The pH of the solution is 3.0
Explanation:
Considering:
[tex]Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}[/tex]
Or,
[tex]Moles =Molarity \times {Volume\ of\ the\ solution}[/tex]
Given :
For [tex]HNO_3[/tex] :
Molarity = 0.0030 M
Volume = 100 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 100×10⁻³ L
Thus, moles of [tex]HNO_3[/tex] :
[tex]Moles=0.0030 \times {100\times 10^{-3}}\ moles[/tex]
Moles of [tex]HNO_3[/tex] = 0.0003 moles
Volume added = 200 mL
Total volume = 200 + 100 mL = 300 mL = 0.3 L
Thus,
[tex]Molarity=\frac{0.0003\ moles}{0.3\ L}=0.001\ M[/tex]
SInce, it is strong acid. Thus, [H⁺] = 0.001 M
pH is defined as the negative logarithm of the concentration of hydrogen ions.
Thus,
pH = - log [H⁺] = - log 0.001 = 3.0
The pH of the solution is 3.0
