An experiment consists of tossing a coin 6 times. Let X be the random variable that is the number of heads in the outcome. Find the mean and variance of X.

Respuesta :

Answer: 3 and 1.5

Step-by-step explanation:

In binomial distribution, the formula to find the mean and variance (respectively) is given by :-

[tex]\mu=np\\ \sigma^2=np(1-p)[/tex]

, where n= Total number of trials.

p= probability of getting success in each trial.

Let X be the random variable that is the number of heads in the outcome.

Given : An experiment consists of tossing a coin 6 times.

i.e. n= 6

Also, total outcomes in coin =2  (tail , head)

Probability of getting head in each trial = (Favorable outcome)/ (Total outcome)

[tex]p=\dfrac{1}{2}[/tex]

Mean = [tex](6)(\dfrac{1}{2})=3[/tex]

Variance = [tex]\sigma^2=6(\dfrac{1}{2})(1-\dfrac{1}{2})[/tex]

[tex]=3(\dfrac{1}{2})=1.5[/tex]

Hence, the mean and variance of X is 3 and 1.5 respectively .