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A bomb calorimeter with a heat capacity of 30 J/C contains 1000 g of water with an initial temperature of 25°C. A 0.5 g sample of a candy bar is placed in a bomb calorimeter and ignited, resulting in a new water temperature of 30°C. What is ΔE for this reaction?

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Answer:

21.05 kJ

Explanation:

The reaction gives out heat. We assume that no heat is lost to that environment except the calorimeter and water.

heat of reaction =  energy absorbed by the calorimeter + energy absorbed by

                               the water

ΔE = 30J/K x 5 K + 1000 g x 4.18 J/g-K * 5 K

     = 21 050 J

     = 21.05 kJ

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