Please help cant find anywhere

Answer:
The option is first one that is
[tex]\frac{m^{7}n^{3}n}{m}[/tex]
Step-by-step explanation:
Given:
[tex]\frac{m^{7}n^{3}}{mn^{-1} },m\neq 0,n\neq 0[/tex]
After negative exponent eliminated we get
[tex]\frac{m^{7}n^{3}n}{m}[/tex]
Negative exponent :
The variable containing negative powers. Here the variable( n⁻¹) is negative exponent.
Law of indices
[tex]a^{-1} = \frac{1}{a}\\\\Here\\n^{-1} = \frac{1}{n}\\\\[/tex]
[tex]\\\textrm{Using law of indices we get}\\\frac{m^{7}n^{3}}{mn^{-1} }=\frac{m^{7}n^{3}}{m\frac{1}{n} } }\\\\ \frac{m^{7}n^{3}}{mn^{-1} }=\frac{m^{7}n^{3}n}{m}[/tex]