A block of wood has a density of 800 kg/m3 . It is placed in a fluid in which it floats with two-thirds of its volume submerged. What is the density of the fluid?

Respuesta :

Answer:

1200 kg/m³

Explanation:

V = Volume

[tex]\rho[/tex] =  Density

o denotes object

f denotes fluid

[tex]V_f=\dfrac{2}{3}V_o[/tex]

The buoyant force balances the weight of the object

[tex]W_o=W_f\\\Rightarrow \rho_oV_og=\rho_fV_fg\\\Rightarrow \dfrac{\rho_o}{\rho_f}=\dfrac{V_f}{V_o}\\\Rightarrow \dfrac{\rho_o}{\rho_f}=\dfrac{\dfrac{2}{3}V_0}{V_0}\\\Rightarrow \dfrac{\rho_o}{\rho_f}=\dfrac{2}{3}\\\Rightarrow \rho_f=\dfrac{3}{2}\rho_o\\\Rightarrow \rho_f=\dfrac{3}{2}\times 800\\\Rightarrow \rho_f=1200\ kg/m^3[/tex]

The density of the fluid is 1200 kg/m³