Respuesta :
Answer : The thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole
Explanation :
First we have to calculate the heat released by the combustion.
[tex]q=c\times \Delta T[/tex]
where,
q = heat released = ?
[tex]c[/tex] = specific heat of calorimeter = [tex]3.640kJ/^oC[/tex]
[tex]\Delta T[/tex] = change in temperature = [tex]19.35^oC[/tex]
Now put all the given values in the above formula, we get:
[tex]q=3.640kJ/^oC\times (19.35)^oC[/tex]
[tex]q=70.43kJ[/tex]
Thus, the heat released by the combustion = 70.43 kJ
Now we have to calculate the molar enthalpy combustion.
[tex]\Delta H=-\frac{q}{n}[/tex]
where,
[tex]\Delta H[/tex] = molar enthalpy combustion = ?
q = heat released = 70.43 kJ
n = number of moles cymene = [tex]\frac{\text{Mass of cymene}}{\text{Molar mass of cymene}}=\frac{1.608g}{164.22g/mol}=0.009792mole[/tex]
[tex]\Delta H=-\frac{70.43kJ}{0.009792mole}=-7193kJ/mole[/tex]
Therefore, the thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole
