Answer:
a) The cell potential energy is -0.01 V
b) The spontaneous chemical reaction - [tex]Sn^{2+}Pb\rightarrow Sn+Pb^{2+}[/tex]
Explanation:
The chemical reaction between lead and tin ions is follows.
[tex]SnPb^{2+}\rightarrow Sn^{2+}+Pb[/tex]
The cell potential can be calculated by using Nernst equation.
[tex][\Delta V=(V_{pb}^{0}-V_{sn}^{0})-\frac{0.592}{n}log\frac{[Sn^{2+}]}{[Pb^{2+}]}[/tex]
[tex]V_{pb}^{0}= -0.126[/tex]
[tex]V_{sn}^{0}= -0.136[/tex]
[tex]n=2[/tex]
[tex][Sn^{2+}]= 0.25M[/tex]
[tex][Pb^{2+}]=5\times 10^{-2}M[/tex]
Substitute the values.
[tex][\Delta V=(-0.125-(-0.136))-\frac{0.592}{2}log\frac{[0.25}{5\times 10^{-2}}[/tex]
[tex]=0.011-0.021=-0.01V[/tex]
Therefore, the cell potential is 0.01V.
b)
The voltage value is negative.The spontaneous eectrochemical reaction is reverse of the electrochemical reaction in part(a)
Therefore, spontaneous reaction is as follows.
[tex]Sn^{2+}Pb\rightarrow Sn+Pb^{2+}[/tex]