Answer: Option 'c' is correct.
Step-by-step explanation:
Since we have given that
[tex]y=2x^2-600x+49000[/tex]
We need to find the number of units in order to minimize cost.
We first derivative w.r.t. x,
[tex]y'=4x-600[/tex]
For critical points:
[tex]y'=0\\\\4x-600=0\\\\4x=600\\\\x=\dfrac{600}{4}\\\\x=150[/tex]
Now, we will check whether it is minimum or not.
We will find second derivative .
[tex]y''=4>0[/tex]
So, it will yield minimum cost.
Minimum cost would be
[tex]y(150)=2(150)^2-600\times 150+49000\\\\y(150)=\$4000[/tex]
Hence, At 150 units, minimum cost = $4000
Therefore, Option 'c' is correct.