Answer:
[tex]x=\frac{1(+/-)\sqrt{197}} {14}[/tex]
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
[tex]ax^{2} +bx+c=0[/tex]
is equal to
[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]
in this problem we have
[tex]7x^{2} -x=7[/tex]
equate to zero
[tex]7x^{2} -x-7=0[/tex]
so
[tex]a=7\\b=-1\\c=-7[/tex]
substitute in the formula
[tex]x=\frac{-(-1)(+/-)\sqrt{-1^{2}-4(7)(-7)}} {2(7)}[/tex]
[tex]x=\frac{1(+/-)\sqrt{197}} {14}[/tex]
