A nuclear power plant operates at 75 percent of its maximum theoretical (Carnot) efficiency between temperatures of 500oC and 350°C. If the plant produces electric energy at the rate of 1.45 Giga-Watts, how much exhaust heat is discharged per hour?

Respuesta :

Answer:

17280 Giga joule

Explanation:

Carnot engine efficiency =[tex]1- \frac{T_{L} }{T_{H} }[/tex]

So maximum efficiency = [tex]1-\frac{350}{500}[/tex] =[tex]0.3[/tex]

Produced energy =1.45 Giga-Watts

This energy is 75% of total theoretical energy produced.

 Let total energy is produced from plant be x.

[tex]x*\frac{75}{100} = 1.4  Giga Watts[/tex]

⇒ x = 1.86 Giga Watts

Energy lost = 1.86-1.4= 0.46 Giga Watts

Now Heat expelled in engine to sink  

   Let total heat provided be y.

       0.3*y= 1.86

      y= 6.2 Giga Watts

Energy lost in engine = 6.2-1.86 =4.34 Giga Watts

Total energy lost = 4.34 Giga Watts + 0.46 Giga Watts =4.8 Giga watts

For calculating per hour energy discharged multiply it by an hour

  =4.8 *60 *60= 17280 Giga joule