Answer:
33.6 J is the work done on the ball.
Option: b
Explanation:
given that,
Mass of the ball (m) is 0.7 kg.
"Initial velocity" of the ball [tex]({V_i}^2)[/tex] is 2 m/s.
"Final velocity" of the ball [tex]({V_f}^2)[/tex] is 10 m/s.
We need to find how much work is done on the ball.
We know that the "work done" on the ball which is moving with a velocity is equal to the change in "kinetic energy" of the object therefore,
[tex]Work done =\frac{1}{2}m\times{V_f}^2-\frac{1}{2}m\times{V_i}^2[/tex]
[tex]Work done =\frac{1}{2}m({V_f}^2-{V_i}^2)[/tex]
Substitute the given values in the the above formula,
[tex]Work done =\frac{1}{2}0.7({10}^2-{2}^2)[/tex]
[tex]Work done =\frac{1}{2}0.7(100-4)[/tex]
[tex]Work done =\frac{1}{2}0.7(96)[/tex]
[tex]Work done =\frac{1}{2}(67.2)[/tex]
Work done = 33.6 J
