The slope of segment CD is 7. The length of segment BC is √50 units and the figure is a square.
Explanation:
Part A
Slope of a segment is calculated as the ratio of rise over run
In this case, C (8,3) and D(7,-4)
The slope is m=Δy/Δx
Δy=-4-3=-7
Δx=7-8=-1
m= -7/-1 =7
The slope is positive as seen in the graph for segment CD
Part B
To find length of a segment, the formula to apply is:
[tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2[/tex]
Given that B(3,8) and C(8,3) then
x₁=3,x₂=8,y₁=8,y₂=3
substitute values in equation as;
[tex]d=\sqrt{(3-8)^2 +(8-3)^2} \\\\d=\sqrt{(-5)^2+(5)^2} \\\\d=\sqrt{25+25} \\d=\sqrt{50} \\\\\\d=7.07[/tex]
The formula used to find length of a segment
Part C
The geometric figure is a Square.The proof is that the length of the segments is equal, √50 units
Lean More
Properties of a square: https://brainly.com/question/1968511
Keywords : geometric, figure, coordinate, vertices,slope, segment
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