Answer:
Magnification, m = 11.61
Explanation:
Given that,
Object distance, u = -36.1 cm
Focal length of the objective lens, f = +39.5 cm
Let v is the image distance. Using the formula of lens equation, we get :
[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}[/tex]
[tex]\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}[/tex]
[tex]\dfrac{1}{v}=\dfrac{1}{39.5}+\dfrac{1}{-36.1}[/tex]
v = -419.39 cm
Magnification of the lens is given by :
[tex]m=\dfrac{v}{u}[/tex]
[tex]m=\dfrac{-419.39}{-36.1}[/tex]
m = 11.61
So, the magnification of the Galilean telescope is 11.61. Hence, this is the required solution.
