Answer: [tex]3.30\times 10^5N/m^2[/tex]
Explanation:
Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.
[tex]P\propto T[/tex] (At constant volume and number of moles)
[tex]{P_1\times T_1}={P_2\times T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = [tex]2.50\times 10^5N/m^2[/tex]
[tex]P_2[/tex] = final pressure of gas = ?
[tex]T_1[/tex] = initial temperature of gas = [tex]35^0C=(35+273)K=308K [/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]-40^0C=(-40+273)K=233K [/tex]
[tex]{2.50\times 10^5N/m^2\times 308}={P_2\times 233}[/tex]
[tex]P_2=3.30\times 10^5N/m^2[/tex]
Therefore, the final gauge pressure in the car tires is [tex]3.30\times 10^5N/m^2[/tex]
