Respuesta :
Answer:
B) Iron (c=0.45 J/g°C)
Explanation:
Given that:-
Heat gain by water = Heat lost by metal
Thus,
[tex]m_{water}\times C_{water}\times (T_f-T_i)=-m_{metal}\times C_{metal}\times (T_f-T_i)[/tex]
Where, negative sign signifies heat loss
Or,
[tex]m_{water}\times C_{water}\times (T_f-T_i)=m_{metal}\times C_{metal}\times (T_i-T_f)[/tex]
For water:
Mass = 120 g
Initial temperature = 21.8 °C
Final temperature = 24.5 °C
Specific heat of water = 4.184 J/g°C
For metal:
Mass = 40.2 g
Initial temperature = 99.3 °C
Final temperature = 24.5 °C
Specific heat of metal = ?
So,
[tex]120\times 4.184\times (24.5-21.8)=40.2\times C_{metal}\times (99.3-24.5)[/tex]
[tex]40.2C_{metal}\left(99.3-24.5\right)=120\times \:2.7\times \:4.184[/tex]
[tex]40.2C_{metal}\left(99.3-24.5\right)=1355.616[/tex]
[tex]C_{metal}=0.45\ J/g^0C[/tex]
This value corresponds to iron. Thus answer is B.
A calorimeter is a heat measuring device that estimates the heat of the chemical or the physical reactions. Iron is the metal that will be used as specific heat (c) is [tex]0.45 \;\rm J/g^{\circ}\;\rm C.[/tex]
What is metal?
Metal is a material that is lustrous, ductile, conductor of heat and electricity. They produce hydroxides, oxides and cations after they lose electrons.
Applying heat given by water = heat lost by metal, the specific heat of the metal can be calculated.
[tex]\rm m_{water}\times C_{water} \times (T_{f}-T_{i}) = - m_{meatl}\times C_{metal} \times (T_{i}-T_{f})[/tex]
Given,
Mass of water = 120 g
The initial temperature of water = 21.8 per degrees Celsius
The final temperature of water = 24.5 per degrees Celsius
Specific heat of water = [tex]4.184 \;\rm J/g^{\circ}\;\rm C.[/tex]
Mass of metal = 40.2 g
The initial temperature of metal = 99.3 per degrees Celsius
The final temperature of metal = 24.5 per degrees Celsius
Specific heat of water = ?
Substituting values in the above equation:
[tex]\begin{aligned} 120 \times 4.184\times (24.5-21.8) &= 40.2 \rm \times C_{metal} \times (99.3-24.5)\\\\&= 40.2 \rm \times C_{metal}(99.3-24.5) = 1355.616\\\\&= 0.45\;\rm J/g^{\circ}C\end{aligned}[/tex]
Therefore, option B. iron is the metal that will be used.
Learn more about heat and calorimeter here:
https://brainly.com/question/7959859
