9. A sailor pulls a boat along a dock using a rope at an angle of 60.0° with the
horizontal. How much work does the sailor do if he exerts a force of 255 N
on the rope and pulls the boat 3.00 m? A girl pulls a wagon along a level path
for a distance of 44 m. The handle of the wagon makes an angle of 22°
above horizontal. If she pulls on the handle with a force of 87 N, how much
work is done?

Respuesta :

Answer: (1) 3.83x10^3 J

Explanation:

(1) Fx=(255N)cos60°

   dx=30.0m

   w=Fx dx =(255)(cos60°)(30.0m)

fichoh

Workdone is the product of the force and the distance moved. Resolving the force applied along the horizontal, the Workdone in both scenario are :

  • 382.5 Nm
  • 3549.26 Nm

Recall :

  • Workdone, W = Force, F × Distance, d

Horizontal component, Fx :

  • Fx = mgCosθ

Fx = 255 × cos60°

Fx = 127.5N

Workdone, W = (Fx) × Distance

Workdone, W = 127.5 × 3 = 382.5 Nm

2.)

Horizontal component, Fx :

  • Fx = mgCosθ

Fx = 87 × cos22°

Fx = 80.665N

Workdone, W = (Fx) × Distance

Workdone, W = 80.665 × 44 = 3549.26 Nm

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