Respuesta :
Answer: (1) 3.83x10^3 J
Explanation:
(1) Fx=(255N)cos60°
dx=30.0m
w=Fx dx =(255)(cos60°)(30.0m)
Workdone is the product of the force and the distance moved. Resolving the force applied along the horizontal, the Workdone in both scenario are :
- 382.5 Nm
- 3549.26 Nm
Recall :
- Workdone, W = Force, F × Distance, d
Horizontal component, Fx :
- Fx = mgCosθ
Fx = 255 × cos60°
Fx = 127.5N
Workdone, W = (Fx) × Distance
Workdone, W = 127.5 × 3 = 382.5 Nm
2.)
Horizontal component, Fx :
- Fx = mgCosθ
Fx = 87 × cos22°
Fx = 80.665N
Workdone, W = (Fx) × Distance
Workdone, W = 80.665 × 44 = 3549.26 Nm
Learn more :https://brainly.com/question/13217627