Answer:
[tex]x=6\times\sqrt{3}[/tex]
Step-by-step explanation:
Given:
[tex]\sqrt{3}x -2=4^{2}[/tex]
To Find:
x =?
Solution:
We have,
[tex]\sqrt{3}x -2=4^{2}\\\\\sqrt{3}x -2=16\\\\\sqrt{3}x=16+2\\\\\sqrt{3}x =18\\\\x=\frac{18}{\sqrt{3} }[/tex]
As square root of 3 is in denominator we will rationalize the denominator i.e multiply and divide by square root 3,so we get
[tex]\therefore x = \frac{18}{\sqrt{3} }\times \frac{\sqrt{3} }{\sqrt{3} } \\ \\\therefore x=\frac{18}{3}\times \sqrt{3}\\\\\therefore x=6\sqrt{3}[/tex]
∴ x = 6√3 is the final answer.
