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The circle below is centered at the point (4,1) and has a radius of length 2.
What is its equation?
O A. (x-1)2 + (y - 4)2 = 4
O B. (x+4)2 + (y- 1)2 = 4
O C. (x-4)2 + (y- 1)2 = 4
O D. (x + 1)2 + (y-4)2 =
22

Respuesta :

absor201

Option C: (x-4)^2+(y-1)^2 = 4 is the right answer

Step-by-step explanation:

Given

Center = (h,k) = (4,1)

Radius = r = 2

The equation of circle in standard form is:

[tex](x-h)^2+(y-k)^2 = r^2[/tex]

Putting the values of h, k and r

[tex](x-4)^2+(y-1)^2 = (2)^2\\(x-4)^2+(y-1)^2 = 4[/tex]

Hence,

Option C: (x-4)^2+(y-1)^2 = 4 is the right answer

Keywords: Equation of circle

Learn more about circle at:

  • brainly.com/question/4694425
  • brainly.com/question/4695279

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