The maximum acceleration is c) [tex]2.38 m/s^2[/tex]
Explanation:
The maximum acceleration of a spring-mass system is given by
[tex]a_{max} = \omega^2 A[/tex]
where
[tex]\omega[/tex] is the angular frequency of the system
A is the amplitude of the motion
For the spring-mass system in this problem, we have
[tex]A=2.2 cm = 0.022 m[/tex] is the amplitude
[tex]\omega=10.4 rad/s[/tex] is the angular frequency
Substituting, we find the maximum acceleration:
[tex]a_{max}=(0.022)(10.4)^2=2.38 m/s^2[/tex]
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