Answer:
Speed of the hawk, v = 40.4 m/s
Explanation:
It is given that,
Exact frequency of the female, f = 785 Hz
Observed frequency of female, f' = 890 Hz
Speed of sound, v = 343 m/s
Let v' is the speed of the hawk. It is based on the concept of Doppler's effect. We know that when the object approaches you, its speed is given by :
[tex]f'=f(\dfrac{v}{v-v'})[/tex]
[tex]890=785\times (\dfrac{343}{343-v'})[/tex]
v' = 40.4 m/s
So, the speed of the hawk is 40.4 m/s. Hence, this is the required solution.
