Answer:
C. [tex]4\cdot 5\cdot 3 = 60[/tex]
Step-by-step explanation:
Given:
Number of sweaters are, [tex]S=4[/tex]
Number of pair of pants are, [tex]P=5[/tex]
Number of pairs of shoes are, [tex]H=3[/tex]
Now, as per question, we have to choose one from each type.
Now, number of ways of choosing one sweater from 4 sweaters is [tex]n(S)= 4\ ways[/tex].
Number of ways of choosing one pair of pants from 5 pair of pants is [tex]n(P)= 5\ ways[/tex].
Number of ways of choosing one pair of shoes from 3 pairs of shoes is [tex]n(H)= 3\ ways[/tex].
Therefore, choosing one from each type is the intersection of all. So,
[tex]n(S\cap P\cap H)=n(S)\cdot n(P)\cdot n(H)\\n(S\cap P\cap H)=4\cdot 5\cdot 3\\n(S\cap P\cap H)=60[/tex]
Therefore, 60 different combinations can be made wearing one of each type.
