Respuesta :
Answer:
(a)13.351 kg of hexamethylene diamine are necessary to yield 26 kg of completely linear nylon 6,6.
(b) 16.790 kg of dipic acid are necessary to yield 26 kg of completely linear nylon 6,6.
Explanation:
Nylon 6,6 compound can be formed by the hexamethylene diamine and adipic acid.
Molecular formula of adipic acid = [tex]C_{6}H_{10}O_{4}[/tex]
Molar mass of adipic acid = 146.14 g/mol
Molecular formula of hexamethylene amine = [tex]C_{6}H_{16}N_{2}[/tex]
Molar mass of hexamethylene damine =116.21 g/mol
Molecular formula of Nylon = [tex]C_{12}H_{22}N_{2}O_{2}[/tex]
Molar mass of adipic acid = 226.32 g/mol
Number of moles of 20 kg Nylon:
[tex]Moles=\frac{Given\,weight}{molecularmass}[/tex]
[tex]Moles=\frac{26000g}{226.32g/mol}=114.89mol[/tex]
To produce Nylon -6,6 requires one mole of adipic acid, one mole of hexamethylenediamine and two moles water.
The weight of adipic acid that required to produce 26 Kg of Nylon 6,6:
[tex]Weight\,of\,adipicacid=Number\,of\,moles \times Molar\,mass\,of\,adipic\,acid[/tex]
[tex]=114.89\times146.14=16790g=16.790\,kg[/tex]
Therefore, 16.790 kg of dipic acid are necessary to yield 26 kg of completely linear nylon 6,6.
The weight of Hexamethylene diamine that required to produce 26 Kg of Nylon 6,6:
[tex]Weight\,of\,Hexamethylene\,diamine=Moles\times Molar\,mass[/tex]
[tex]=116.21\times114.89=13351g=13.351\,kg[/tex]
Therefore, 13.351 kg of hexamethylene diamine are necessary to yield 26 kg of completely linear nylon 6,6.
