Answer: The volume of Barium hydroxide require is 110milliLitres
Explanation:
The neutralization equation;
Ba(OH)2 (aq) + H2SO4 (aq) → BaSO4 (s) + 2H20(1)
Using the relation
CaVa/CbVb = Na/Nb
Ca= molar concentration of acid=1.4M
Cb=molar concentration of base=?
Va= volume of acid =55mL
Vb= Volume of base =?
Na= mole of acid from stoichiometric equations =1
Nb= mole of base from stoichiometric equation 1
(1.4 × 55)/(0.7 ×Vb) = 1/1
Vb= 110mL
Therefore the volume of Ba(OH)2 requires to neutralize the Sulfuric acid is 110millilitres
