Answer:
For a: The isotopic symbol of the above atom will be [tex]_{53}^{131}\textrm{I}[/tex]
For b: The isotopic symbol of the above atom will be [tex]_{77}^{192}\textrm{Ir}[/tex]
For c: the isotopic symbol of the above atom will be [tex]_{62}^{153}\textrm{Sm}[/tex]
Explanation:
The isotopic representation of an atom is: [tex]_Z^A\textrm{X}[/tex]
where,
Z = Atomic number of the atom
A = Mass number of the atom
X = Symbol of the atom
Atomic number of iodine = 53
Mass number of iodine = 131
Symbol of iodine = I
The isotopic symbol of the above atom will be [tex]_{53}^{131}\textrm{I}[/tex]
Atomic number of iridium = 77
Mass number of iridium = 192
Symbol of iridium = Ir
The isotopic symbol of the above atom will be [tex]_{77}^{192}\textrm{Ir}[/tex]
Atomic number of samarium = 62
Mass number of samarium = 153
Symbol of samarium = Sm
The isotopic symbol of the above atom will be [tex]_{62}^{153}\textrm{Sm}[/tex]