Answer:
Increase by a factor of 4.
Explanation:
The acceleration of a car moving with speed v in a circle of radius R is given by:
[tex]a=\frac{v^2}{R}.[/tex]
Now if we double the speed [tex]v[/tex] in the equation above, it becomes [tex]2v[/tex]. Thus:
[tex]a=\frac{v^2}{R}\:\: {\rightarrow}\:\: a_n=\frac{(2v)^2}{R}=4\frac{v^2}{R}=4a.[/tex]
Therefore the acceleration is increased by a factor of 4.
