Respuesta :
Answer:
4649.16 g
Explanation:
We are given;
- The equation for the reaction
2C₄H₁₀ + 13O₂→ 8CO₂ + 10H₂O
- Mass of C₄H₁₀
We are required to determine the mass of water produced.
Step: Determine the number of moles of C₄H₁₀
We know that, moles = Mass ÷ Molar mass
Molar mass of C₄H₁₀ is 58.14 g/mol
Therefore;
Moles of C₄H₁₀ = 3000 g ÷ 58.14 g/mol
= 51.5996
= 51.60 moles
Step 2: Determine the number of moles of water
- From the equation, 2 moles of C₄H₁₀ reacts to produce 10 moles of water
Therefore;
Moles of water = Moles of C₄H₁₀ × 10/2
= 51.60 moles × 5
= 258 moles
Step 3: Determine the mass of water produced
We know that; mass = moles × molar mass
Molar mass of water = 18.02 g/mol
Thus;
Mass of water = 258 moles × 18.02 g/mol
= 4649.16 g
Therefore, the mass of water produced will be 4649.16 g
Answer:
1298 g
Explanation:
Data Given
mass of C₄H₁₀ = 3000 g
mass of water H₂O (Theoretical yield) = ?
Reaction Given:
2C₄H₁₀ + 13O2 -----> 8CO₂ + 10H₂O
Solution:
First find the mass of C₄H₁₀ from the reaction that it give how many grams of water.
Look at the reaction
2C₄H₁₀ + 13O2 -----> 8CO₂ + 10H₂O
2 mol 10 mol
So 2 mole of C₄H₁₀ give 10 moles of H₂O
Now
convert the moles into mass for which we have to know molar mass of C₄H₁₀ and H₂O
Molar mass of C₄H₁₀ = 4 (12) + 10(16) = 48 + 160
Molar mass of C₄H₁₀ = 208 g/mol
mass of C₄H₁₀
mass in grams = no. of moles x molar mass
mass of C₄H₁₀ = 2 mol x 208 g/mol
mass of C₄H₁₀ = 416 g
Molar mass of H₂O = 2+ 16
Molar mass of H₂O = 18g/mol
mass of H₂O
mass in grams = no. of moles x molar mass
mass of H₂O = 10 mol x 18 g/mol
mass of H₂O = 180 g
So,
416 g of C₄H₁₀ gives 180 g of water ( H₂O ) then how many grams of water will produced by 3000 g of C₄H₁₀
Apply unity Formula
416 g of C₄H₁₀ ≅ 180 g of water ( H₂O )
3000 g of C₄H₁₀ ≅ X g of water ( H₂O )
By cross multiplication
g of water ( H₂O ) = 180 g x 3000 g / 416 g
g of water ( H₂O ) = 1298 g
1298 g of water (H₂O) will produced by 3000 g of C₄H₁₀
So
The Theoretical yield of water (H₂O) = 1298 g
