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Light with a wavelength of 614.5 nm looks orange. What is the energy, in joules, per photon of this orange light? What is the energy in eV (1 eV = 1.602 × 10−19 J)?

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igeclement43

Answer: The energy is 2.00eV

Explanation:

From Planck's theory

E=hf = hc/k

Where h is the planck constant =

6.6×10^-34m2kg/s

C= speed of light =3.0 ×10^8m/s

k= wavelength = 651.4nm=651.4 ×10^-9

E=(6.6×10^-34 × 3.0 ×10^8)/(651.4×10^-9)

E=3.22 × 10^-19J

1eV = 1.602×10^-19J

E=2.00eV

The energy is 2.00eV

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