Answer:
the velocity of the fuel through the nozzle v= 6.45 ft/s
Explanation:
Given values
Volume = 687 gallons= [tex]2.6 m^3[/tex]
9 refueling transfers
dia of nozzle d= 1.45 inches
each refueling took 2.41 minutes to perform. t= 2.41×60×9= 1247.4 sec
Volume of fuel pumped in time t is give by
V= Avt
A= area of mouth of pipe
v= flow rate
t= time
A= πr^2
A= [tex]\pi\times (\frac{0.0368}{2} )^2 = 0.00106 m^2[/tex]
now substituting the values in equation 1 we get
[tex]2.6= 0.00106\times v \times1247.4[/tex]
v= 1.966 m/sec
v= 6.45 ft/s
the velocity of the fuel through the nozzle v= 6.45 ft/s
