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How many atoms of oxygen are contained in 88.2 kg of aluminum carbonate? Write value in E-notation with at least three significant figures. The molar mass of aluminum carbonate is 233.99 g/mol, but you will need to write the formula so that you can define the counting relationship.

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Answer:

There are 2.04x10²⁷ atoms of O

Explanation:

Aluminum carbonate's formula is: Al₂(CO₃)₃

This compound has 2 moles of Aluminum and 3 moles of carbonate, and carbonate has 1 mol of C plus 3 moles of O. Finally we have 9 moles of O.

9 moles of O, are in 1 mol of salt which weighs 233.99 grams

So if in 233.99 g of salt ____ are ___ 9 moles O

88200 g of salt ___ are ____  (88200 . 9) / 233.99 = 3392.4 moles of O

1 mol of O __ has __ NA atoms

3392.4 moles of O __ has ___ (3392.4 . NA) / 1 =  2.04x10²⁷

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