Answer:
The dimensions of the rectangle are
length = 34 yards
width = 15 yards
Step-by-step explanation:
Given:
The shape is of rectangle,
Width of rectangle = x
Area of rectangle = 510 yd²
According to the given condition
Length of rectangle = 4 + 2x
To Find:
length =?
Width = ?
Solution:
We know that,
[tex]\textrm{Area of rectangle} = Length\times Width[/tex]
On substituting the given values we get
[tex]510 = (4 + 2x)\times x\\510 = 4x+2x^{2}\ \textrm{using distributive property}\\\textrm{dividing throughout by two}\\255=2x+x^{2} \\\\x^{2} +2x -255 = 0\\[/tex]
Which is a quadratic equation so we will apply splitting the middle term that is factorization we get
∴ [tex]x^{2}+ 17x -15x -255=0\\x(x+17)-15(x+17)=0\\(x-15)(x+17)=0\\\therefore x-15 =0\ or\ x+17=0\\\\\textrm{x cannot be negative i.e -17}\\\therefore x=15[/tex]
∴ Width x = 15 yard
∴ Length = 4 + 2x = 4 +2 × 15 = 34 yard
The dimensions of the rectangle are
length = 34 yards
width = 15 yards
