In the circuit below, the impedance Z1 dissipates 10 kW with a power factor of 0.85 lagging. Z2 draws 12 kVA apparent power with a power factor of 0.75 leading. The frequency of the source is 60 Hz.

Respuesta :

Answer:

The impedance Z₁ is [tex]10+j6.19\ kVA[/tex]

Explanation:

Given that,

Dissipates power = 10 kW

Power factor = 0.85

Apparent power = 0.75

Frequency = 60 Hz

Suppose we need to calculate the impedance Z₁

The impedance Z₁ dissipates 10 kW with a power factor of 0.85 lagging

[tex]\cos\theta=0.85[/tex]

[tex]\theta=\cos^{-1}(0.85)[/tex]

[tex]\theta=31.78^{\circ}[/tex]

We need to calculate the impedance Z₁

Using formula of  the impedance Z₁

[tex]z_{1}=P_{1}+jQ_{1}[/tex]

[tex]z_{1}=P_{1}+j\dfrac{10}{0.85}\sin\theta[/tex]

Put the value into the formula

[tex]z_{1}=10+j\dfrac{10}{0.85}\sin31.78[/tex]

[tex]z_{1}=10+j6.19\ kVA[/tex]

Hence, The impedance Z₁ is [tex]10+j6.19\ kVA[/tex]