Pressure: The tip of a nail has a radius of 0.0025 m.If the weight of a person (773 N) is applied to the tip of this nail, what is the resulting pressure from this force?

Respuesta :

The pressure is [tex]3.94\cdot 10^7 Pa[/tex]

Explanation:

First of all, we calculate the area of the tip of the nail, which is given by:

[tex]A=\pi r^2[/tex]

where

r = 0.0025 m is the radius

Substituting,

[tex]A=\pi (0.0025)^2=1.96\cdot 10^{-5} m^2[/tex]

Then we can calculate the pressure exerted by the person on the nail, which is

[tex]p=\frac{F}{A}[/tex]

where

F = 773 N is the force exerted (the weight of the man)

[tex]A=1.96\cdot 10^{-5} m^2[/tex] is the area

Substituting,

[tex]p=\frac{773}{1.96\cdot 10^{-5} m^2}=3.94\cdot 10^7 Pa[/tex]

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