To solve this problem it is necessary to apply the concepts related to the described wavelength through frequency and speed. Mathematically it can be expressed as:
[tex]\lambda = \frac{v}{f}[/tex]
Where,
[tex]\lambda =[/tex] Wavelength
f = Frequency
v = Velocity
Our values are given as,
[tex]f = 2.8*10^3Hz[/tex]
[tex]v = 340m/s \rightarrow[/tex] Speed of sound
Keep in mind that we do not use the travel speed of the ambulance because we are in front of it. In case it approached or moved away we should use the concepts related to the Doppler effect:
Replacing we have,
[tex]\lambda = \frac{340}{2.8*10^3}[/tex]
[tex]\lambda = 0.1214m[/tex]
Therefore the frequency that you hear if you are standing in from of the ambulance is 0.1214m
