Two satellites are in circular orbits around a planet that has radius 9.00x10^6 m. One satellite has mass 53.0 kg , orbital radius 8.20×10^7 m, and orbital speed 4800 m/s. The second satellite has mass 54.0 kg and orbital radius 7.00×10^7 m.

A) What is the orbital speed of this second satellite?
v=?

Respuesta :

Answer:

The orbital speed of this second satellite is 5195.16 m/s.

Explanation:

Given that,

Orbital radius of first satellite [tex]r_{1}= 8.20\times10^{7} [/tex]

Orbital radius of second satellite [tex]r_{2}=7.00\times10^{7}\ m[/tex]

Mass of first satellite [tex]m_{1}=53.0\ kg[/tex]

Mass of second satellite [tex]m_{2}=54.0\ kg[/tex]

Orbital speed of first satellite = 4800 m/s

We need to calculate the orbital speed of this second satellite

Using formula of orbital speed

[tex]v=\sqrt{\dfrac{GM}{r}}[/tex]

From this relation,

[tex]v_{1}\propto\dfrac{1}{\sqrt{r}}[/tex]

Now, [tex]\dfrac{v_{1}}{v_{2}}=\sqrt{\dfrac{r_{2}}{r_{1}}}[/tex]

[tex]v_{2}=v_{1}\times\sqrt{\dfrac{r_{1}}{r_{2}}}[/tex]

Put the value into the formula

[tex]v_{2}=4800\times\sqrt{\dfrac{ 8.20\times10^{7}}{7.00\times10^{7}}}[/tex]

[tex]v_{2}=5195.16\ m/s[/tex]

Hence, The orbital speed of this second satellite is 5195.16 m/s.