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Two children are sitting on opposite ends of a seesaw of negligible mass. Of 40 kg child is 2.0 m from the pivot point, how far from the pivot point will the other 30 kg child sit on the seesaw to be at equilibrium?

Respuesta :

Answer:

Distance of the second child from the pivot point will be 2.66 m

Explanation:

We have given mass of the first child [tex]m_1=40kg[/tex]

Distance from the pivot point [tex]d_1=2m[/tex]

Mass of the second child [tex]m_2=30kg[/tex]

We have to find the distance of the second child from the pivot point

For this we have to balance the moment

So [tex]m_1d_1=m_2d_2[/tex]

[tex]40\times 2=30\times d_2[/tex]

[tex]d_2=2.66m[/tex]

So the distance of the second child from the pivot point point will be 2.66 m

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