Answer:
Work done, W = 10195.92 Joules
Explanation:
Given that,
Mass of the crate, m = 170 kg
Distance, d = 10.2 m
The coefficient of friction, [tex]\mu=0.6[/tex]
Let W is the work done by the mover. It is given by in terms of coefficient of friction as :
[tex]W=\mu mg\times d[/tex]
[tex]W=0.6\times 170\times 9.8 \times 10.2[/tex]
W = 10195.92 Joules
So, the work done by the mover is 10195.92 Joules. Hence, this is the required solution.
