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A flight attendant pushes a beverage car on an aircraft. Her mass is 75 kg and the cart’s mass is 27 kg. Calculate the acceleration produced when the flight attendant exerts a backward force of 155 N on the floor. All forces opposing the motion, such as friction on the cart’s wheels and air resistance, total 18 N.

Respuesta :

Answer:

a = 1.34 m/s²

Explanation:

given,

mass of the attendant(M) = 75 Kg

mass of cart (m)= 27 Kg

Backward force exerted on floor (F)= 155 N

frictional force on the cart (f)= 18 N

acceleration

[tex]a = \dfrac{F_{net}}{M+m}[/tex]

F_{net} = F - frictional force

F_{net} = 155 N - 18 N

F_{net} = 137 N

now,

[tex]a = \dfrac{137}{75 + 27}[/tex]

[tex]a = \dfrac{137}{102}[/tex]

a = 1.34 m/s²

the acceleration produced when flight attendant is equal to  a = 1.34 m/s²

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