Answer: [tex]1.54m^3[/tex]
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas at STP = 1 atm
[tex]P_2[/tex] = final pressure of gas = 2.67 atm
[tex]V_1[/tex] = initial volume of gas = [tex]3.61m^3[/tex]
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas at STP = [tex]0^oC=273+0=273K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]37.9^oC=273+37.9=310.9K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{1atm\times 3.61m^3}{273K}=\frac{2.67\times V_2}{310.9K}[/tex]
[tex]V_2=1.54m^3[/tex]
Thus the final volume will be [tex]1.54m^3[/tex]
