A boy and a girl are balanced on a massless seesaw. The boy has a mass of 60 kg and the girl's mass is 50 kg. If the boy sits 1.5 m from the pivot point on one side of the seesaw, where must the girl sit on the other side for equilibrium

Question

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Respuesta :

abidemiokin abidemiokin · Answer 1 · 2019-12-10T07:15:09+01:00

Answer: 1.8m

Explanation:

Using the principle of moment to solve the question which states that the sum of clockwise moment is equal to the sum of anticlockwise moments.

The boy moves in the clockwise direction towards the pivot while the girl moves in the anticlockwise direction towards the pivot.

Since moment = force × perpendicular distance

CW moments = 60×1.5 = 90Nm

ACW moments = 50×x = 50x

Equating both moments to get 'x'

90 = 50x

x =9/5

x = 1.8m

This shows that the girl must sit 1.8m from the other side for equilibrium.:

okpalawalter8 okpalawalter8 · Answer 2 · 2022-04-12T11:10:27+02:00

The position must the girl sits on the other side for equilibrium is mathematically given as

x = 1.8m

What position must the girl sit on the other side for equilibrium?

Question Parameter(s):

Generally, the equation for the moment is mathematically given as

m= force * perpendicular distance

Therefore

CWm = 60×1.5

CWm = 90Nm

Where

ACWm= 50×x

ACWm= 50x

In conclusion,

90 = 50x

x =9/5

x = 1.8m