Answer:
Option (D) is correct
[tex](x-2)^{2} +(y+5)^{2} = 9[/tex]
Step-by-step explanation:
A circle has (a , b ) are the coordinates of the centre and [tex]r = radius[/tex] .
Given.
A circle is centered at (2,-5) and has radius 3
Let [tex]a=2[/tex] and [tex]b=-5[/tex] and [tex]r=3[/tex]
The standard form of the circle is.
[tex](x-a)^{2} +(y-b)^{2} = r^{2}[/tex]------(1)
Put a, b and r value in equation 1.
[tex](x-2)^{2} +(y-(-5))^{2}= 3^{2}[/tex]
[tex](x-2)^{2} +(y+5)^{2} = 9[/tex]
So. the standard form of equation is.
[tex](x-2)^{2} +(y+5)^{2}= 9[/tex]
