The vertex form of the quadratic equation is:
y = (x + 2/4)^2 + 3/4.
For a quadratic function with vertex (h, k), the vertex form is:
y = a*(x - h)^2 + k
And for a general quadratic function:
y = a*x^2 + b*x + c
The value of h is given by:
h = -b/2a
Then, in our case:
y = x^2 + x + 1
The value of h is:
h = -1/2 =
To get the value of k, we evaluate the function in h.
y = (-1/2)^2 - 1/2 + 1 = 1/4 - 1/2 + 1 = 1/4 - 2/4 + 4/4 = 3/4
So the vertex is at (-2/4, 3/4), then the vertex form is:
y = (x + 2/4)^2 + 3/4.
If you want to learn more about quadratic functions, you can read:
https://brainly.com/question/1214333
Answer:
f(x) = (x + 1/2)^2 + 3/4
Step-by-step explanation:
took it on edge
