Answer:
[tex]\large\boxed{y=\dfrac{12}{11}x-\dfrac{8}{11}}[/tex]
[tex]\large\boxed{slope=\dfrac{12}{11}}\\\\\boxed{y-intercept=-\dfrac{8}{11}}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
We have the equation:
[tex]-12x+11y=-8[/tex] add 12x to both sides
[tex]-12x+12x+11y=12x-8[/tex]
[tex]11y=12x-8[/tex] divide both sides by 11
[tex]\dfrac{11y}{11}=\dfrac{12x}{11}-\dfrac{8}{11}[/tex]
[tex]y=\dfrac{12}{11}x-\dfrac{8}{11}[/tex]
