A fisherman fishing from a pier observes that the float on his line bobs up and down, taking 2.4 s to move from its highest point to its lowest point. He also estimates that the distance between adjacent wave crests is 48 m. What is the speed of the waves going past the pier?

Respuesta :

Answer:

Speed of the wave, v = 10 m/s

Explanation:

Given that,

The distance between adjacent wave crests is 48 m, [tex]\lambda=48\ m[/tex]

Time taken to move highest point to the lowest pint, T = 2.4 s

For a full period, time taken is,

[tex]\dfrac{1}{2T}=2.4[/tex]

T = 4.8 s

Let v is the speed of the waves going past the pier. It is equal to the product of frequency and wavelength. It is equal to :

[tex]v=f\times \lambda[/tex]

[tex]v=\dfrac{1}{T}\times \lambda[/tex]

[tex]v=\dfrac{1}{4.8}\times 48[/tex]

v = 10 m/s

So, the speed of the wave is 10 m/s. Hence, this is the required solution.