Answer:
Speed of the wave, v = 10 m/s
Explanation:
Given that,
The distance between adjacent wave crests is 48 m, [tex]\lambda=48\ m[/tex]
Time taken to move highest point to the lowest pint, T = 2.4 s
For a full period, time taken is,
[tex]\dfrac{1}{2T}=2.4[/tex]
T = 4.8 s
Let v is the speed of the waves going past the pier. It is equal to the product of frequency and wavelength. It is equal to :
[tex]v=f\times \lambda[/tex]
[tex]v=\dfrac{1}{T}\times \lambda[/tex]
[tex]v=\dfrac{1}{4.8}\times 48[/tex]
v = 10 m/s
So, the speed of the wave is 10 m/s. Hence, this is the required solution.