If F1 is the magnitude of the force exerted
by the Earth on a satellite in orbit about the
Earth and F2 is the magnitude of the force
exerted by the satellite on the Earth, then
which of the following is true?1. F2 > F1.
2. F2 ≫ F1.
3. F1 = F2.
4. F1 > F2.
5. F1 ≫ F

Respuesta :

Answer: 3. F1 = F2

Explanation:

According to Newton's law of Gravitation, the force [tex]F[/tex] exerted between two bodies or objects of masses [tex]M[/tex] and [tex]m[/tex] and separated by a distance [tex]r[/tex] is equal to the product of their masses divided by the square of the distance:  

[tex]F=G\frac{Mm}{r^2}[/tex] (1)

Where [tex]G[/tex]is the gravitational constant

Now, in the especific case of the Earth and the satellite, where the Earth has a mass [tex]M[/tex] and satellite a mass [tex]m[/tex], being both separated a distance [tex]r[/tex], the force exerted  by the Earth on the satellite is:

[tex]F1=G\frac{Mm}{r^2}[/tex]   (2)

And the force  exerted by the satellite on the Earth is:

[tex]F2=G\frac{Mm}{r^2}[/tex]   (3)

As we can see equations (2) and (3) are equal, hence the magnitude of the gravitational force is the same for both:

[tex]F1=F2[/tex]