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The eardrum is a membrane located in the middle ear that vibrates when sound waves hit it. Assume an eardrum has an area of 5.07 x 10^−5 m^2.
(a) calculate the average sound power incident on an eardrum at the threshold of pain, which corresponds to an intensity of 1.00 W/m^2.
(b) How much energy is transferred to the eardrum exposed to this sound for 1.00 min?

Respuesta :

Answer:

[tex]5.07\times 10^{-5}\ W[/tex]

0.003042 J

Explanation:

I = Hearing intensity = [tex]1\ W/m^2[/tex]

A = Area = [tex]5.07\times 10^{-5}\ m^2[/tex]

Power is given by

[tex]P=IA\\\Rightarrow P=1\times 5.07\times 10^{-5}\\\Rightarrow P_p=5.07\times 10^{-5}\ W[/tex]

The power which causes pain is [tex]5.07\times 10^{-5}\ W[/tex]

t = Time the eardrum is exposed to sound = 1 min = 60 s

Energy is given by

[tex]E=Pt\\\Rightarrow E=5.07\times 10^{-5}\times 60\\\Rightarrow E=0.003042\ J[/tex]

The energy transfered to the eardrum is 0.003042 J