Answer:
The recoil velocity is 0.819 m/s.
Explanation:
Given that,
Mass of ball m= 7.5 kg
Velocity v= 8.85 m/s
Mass of performer m'= 73.5 kg
Suppose if the performer is on nearly friction less roller skates, we need to calculate his recoil velocity
We need to calculate the recoil velocity
Using law of conservation momentum
[tex]mv=(m+m')v'[/tex]
Where, m = mass of ball
m' = mass of performer
v = velocity of ball
Put the value into the formula
[tex]v'=\dfrac{mv}{m+m'}[/tex]
Put the value into the formula
[tex]v'=\dfrac{7.5\times8.85}{7.5+73.5}[/tex]
[tex]v'=0.819\ m/s[/tex]
Hence, The recoil velocity is 0.819 m/s.
